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tolong dibantu ya kak

Ditulis GhulamID Jumat, 11 Februari 2022 Tulis Komentar Edit

Tolong dibantu ya kak

jawaban soal Matematika

Penjelasan dengan langkah-langkah:

Bentuk Akar

1). √50 = √(25 x 2) = 5√2

2). √20 = √(4 x 5) = 2√5

3). √40 = √(4 x 10) = 2√10

4). 2√3(√40 + √12) = 2√120 + 2√36 = 2√(4 x 30) + 2(6) = 2(2)√30 + 12 = 4√30 + 12

5). (√2 + √5)(√2 - √5) = (√2)² - (√5)² = 2-5 = -3

6). (2√5 - 3√3)(2√5 + 3√3) = (2√5)² - (3√3)² = (2²√5²) - (3²√3²) = 4(5) - 3(3) = 20-9 = 11

7). (4√7)² - (2√3)² = (4²√7²) - (2²√3²) = 16(7) - 4(3) = 112 - 12 = 100

semoga membantu

NOMOR 1.

$\sqrt{50} = \sqrt{25 \times 2} = 5 \sqrt{2}$

NOMOR 2.

$\sqrt{20} = \sqrt{4 \times 5} = 2 \sqrt{5}$

NOMOR 3.

$\sqrt{40} = \sqrt{4 \times 10} = 2 \sqrt{10}$

NOMOR 4.

$2 \sqrt{3} \: (\sqrt{40} + \sqrt{12})$

$= 2 \sqrt{3} \: (\sqrt{4 \times 10} + \sqrt{4 \times 3})$

$= 2 \sqrt{3} \: (2 \sqrt{10} + 2 \sqrt{3})$

$= 4 \sqrt{30} + 4 \sqrt{9}$

$= 4 \sqrt{30} + 4 \times 3 = 4 \sqrt{30} + 12$

NOMOR 5.

$(\sqrt{2} + \sqrt{5})(\sqrt{2} - \sqrt{5})$

$= (\sqrt{2})(\sqrt{2} - \sqrt{5}) + (\sqrt{5})(\sqrt{2} - \sqrt{5})$

$= \sqrt{4} - \sqrt{10} + \sqrt{10} - \sqrt{25}$

$= \sqrt{4} - \sqrt{25} = 2 - 5 = ( - 3)$

NOMOR 6.

$(2 \sqrt{5} - 3 \sqrt{3})(2 \sqrt{5} + 3 \sqrt{3})$

$= (2 \sqrt{5})(2 \sqrt{5} + 3 \sqrt{3}) - (3 \sqrt{3})(2 \sqrt{5} + 3 \sqrt{3})$

$= 4 \sqrt{25} + 6 \sqrt{15} - 6 \sqrt{15} - 9 \sqrt{9}$

$= 4 \sqrt{25} - 9 \sqrt{9}$

$= 4 \times 5 - 9 \times 3 = 20 - 27 = ( - 7)$

NOMOR 7.

${(4 \sqrt{7})}^{2} - {(2 \sqrt{3})}^{2}$

$= (4 \sqrt{7})(4 \sqrt{7}) - (2 \sqrt{3})(2 \sqrt{3})$

$= 16 \sqrt{49} - 4 \sqrt{9}$

$= 16 \times 7 - 4 \times 3 = 112 - 12 = 100$

Baca Juga:

Sumber : https://brainly.co.id/tugas/52218399

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